From my understanding of how PageRank works, it would be impossible for the page to get anything higher than a PR5 if no page higher than a PR5 linked to it.
Ok then, how do sites get a better PR then? If you need a higher PR Page to link to you to get that PR, how did the pages with higher PR than you get there in the first place?? Kinda like if nothing sticks to Teflon, how do they get the Teflon to stick to the pan??
Seriously though, PageRank is a measure of importance in which each link is a vote, but not all votes are equal. So, a PR 1 link is not as strong a vote as a PR 10 link, and you may need 1,000,000 PR 1 votes to equal the value of 1 PR 10 vote. But the fact remains there is a point at which enough PR 1 links will be equal to the value of a PR 10 link.
PageRank is a very simple algorithm:
Value of PageRank of all links in = PageRank of a page. Repeat until values stop changing. (this is a recursive algo, that is, if the value of my PR changes, after each time it is calculated, so do the PRs of all pages I link to, changing my PR... ad nauseam).
PageRank, quite simply, does not concern itself with any other factor.
Think of it like cooking. An algorithm is like a recipe. It takes ingredients (factors), in varying quantities (weighting of factors) and pops out a cooked meal (SERP). Now, the quality of anyone ingredient is independant of any other, that is the chilli you use is good or bad based upon where it was grown. So, PageRank is calculated independant of any other factor, and only looks at links.
Now, an Algorithm change is like a recipe change. Instead of using sugar, you use Palm Sugar. Instead of Soya Sauce, Kecap Manis. That changes the flavour, and thus the outcome of the meal (SERP). Ditto if you use 10 chillis instead of one.
In the end, questions regarding maximum PageRank acheivable in Scenario X are pretty pointless. The relevant question to ask is how to improve PageRank, and the answer to that is very simple: get links in from other sites. Each and every link in does increase PageRank, the question is simply by how much.